Physics

The slope for the up escalator averaged out to be .5 m/s since it took somewhat 20 seconds to recover up the 10 meters that we make The slope of the down (-) escalator averaged out to be -.4 m/s + 10 because it took the object 25 seconds to go 10 meters. For our data, we individually measured a stair which dark-skinned out to be .3 meters and we marked on the stairs so we could count each one that went by until we saw the sucker again, and we found that there were 30 stairs. So .3 meters x 30 stairs = 10 meters = Total outperform of stair case. then(prenominal) we placed an object, a person, on the up escalator, and tested how gigantic it would bow the person to get the precede of the stair case, the sum distance being 10 meters. Since we looked at qualifying to the top as positive, the initial position was secret code because it started at nought meters and was working their way to the top to 10 meters. After 8 trials, we averaged our numbers out and got 20. 00434 seconds, which is approximately 20 seconds. Then we did a variety and set up 10m/20s = x(m)/1s and got .5.

So the equation for this would be position (x) (m) = (.5m/s)(t) We did the resembling thing for the down escalator and got the same size of it of ten meters. Since we were going down we look at it as a forbid direction and our intitial position would be 10 meters. After 8 trials, we averaged out to be 25.0065 seconds, so approximately 25 seconds. Similar to the first one, we did a conversion and got .4 m/s as the speed and since it was a negative velocity, it was going -.4 m/s. The equation for the down escaslator would be po sition(x)= (.4m/s)(t) + 10mIf you call for ! to get a full essay, order it on our website: BestEssayCheap.com

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